San Juan I, Municipality of Ternate, Province of Cavite

Summary data
Typebarangay
Island groupLuzon
RegionCALABARZON (Region IV‑A)
ProvinceCavite
MunicipalityTernate
Postal code4111
Population (2015)2,737
Philippine major island(s)Luzon
Coordinates14.2941, 120.7401

San Juan I is a barangay in the municipality of Ternate, in the province of Cavite. Its population as determined by the 2015 Census was 2,737. This represented 11.82% of the total population of Ternate.

Demographics

Population by age group

According to the 2015 Census, the age group with the highest population in San Juan I is 10 to 14, with 291 individuals. Conversely, the age group with the lowest population is 80 and over, with 23 individuals.

details
Age groupPopulation (2015)
Under 145
1 to 4224
5 to 9273
10 to 14291
15 to 19271
20 to 24262
25 to 29217
30 to 34224
35 to 39206
40 to 44176
45 to 49148
50 to 54122
55 to 5994
60 to 6467
65 to 6937
70 to 7429
75 to 7928
80 and over23
Total2,737

Historical population

The population of San Juan I grew from 1,853 in 1995 to 2,737 in 2015, an increase of 884 people. The latest census figures in 2015 denote a positive growth rate of 1.79%, or an increase of 243 people, from the previous population of 2,494 in 2010.

Census datePopulationGrowth rate
1,853
2,1273.00%
2,5732.66%
2,494-1.13%
2,7371.79%

Location

San Juan I is situated at approximately 14.2941, 120.7401, in the island of Luzon. Elevation at these coordinates is estimated at 17.0 meters or 55.8 feet above mean sea level.


Adjacent barangays

San Juan I shares a common border with the following barangay(s):

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Notes

  1. Data on population is from the Philippine Statistics Authority.
  2. Postal code information is from the Philippine Postal Corporation.