San Juan II, Municipality of Ternate, Province of Cavite

Summary data
Typebarangay
Island groupLuzon
RegionCALABARZON (Region IV‑A)
ProvinceCavite
MunicipalityTernate
Postal code4111
Population (2015)1,490
Philippine major island(s)Luzon
Coordinates14.3007, 120.7297

San Juan II is a barangay in the municipality of Ternate, in the province of Cavite. Its population as determined by the 2015 Census was 1,490. This represented 6.43% of the total population of Ternate.

Demographics

Population by age group

According to the 2015 Census, the age group with the highest population in San Juan II is 5 to 9, with 173 individuals. Conversely, the age group with the lowest population is 75 to 79, with 11 individuals.

details
Age groupPopulation (2015)
Under 120
1 to 4145
5 to 9173
10 to 14140
15 to 19129
20 to 24116
25 to 29117
30 to 34121
35 to 39112
40 to 4472
45 to 4987
50 to 5461
55 to 5962
60 to 6461
65 to 6936
70 to 7412
75 to 7911
80 and over15
Total1,490

Historical population

The population of San Juan II grew from 1,048 in 1995 to 1,490 in 2015, an increase of 442 people. The latest census figures in 2015 denote a positive growth rate of 1.36%, or an increase of 102 people, from the previous population of 1,388 in 2010.

Census datePopulationGrowth rate
1,048
1,2323.53%
1,4782.54%
1,388-2.26%
1,4901.36%

Location

San Juan II is situated at approximately 14.3007, 120.7297, in the island of Luzon. Elevation at these coordinates is estimated at 7.1 meters or 23.3 feet above mean sea level.


Adjacent barangays

San Juan II shares a common border with the following barangay(s):

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Notes

  1. Data on population is from the Philippine Statistics Authority.
  2. Postal code information is from the Philippine Postal Corporation.